Perhitungan Sheet Pile [PDF]

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PERENCANAAN SHEET PILE Lokasi STA. 2+250 Data tanah A



Kedalaman 0 - 2.5 m :



C =



0.32 kg/cm2



w =



0.996 t/m3



 =



11 0



Gs =



2.634 gr/cc



W = e =



54.77 % W x Gs



 = (1+W) x Gs x w



=



54.77% x 2.634



=



1.443



=



(1 + 54.77%) x 2.634 x 0.996



=



1.662 gr/cc



=



0.680 A



1+e Ka1 = A



1+ 1.443



tg2 (45 - /2)



tg2 (45 - 11/2)



Kedalaman 2.5 -8.5 m :



C =



0.26 kg/cm2



w =



0.996 t/m3



 =



70



Gs =



2.621 gr/cc



W = e =



=



51.05 % W x Gs



 = (1+W) x Gs x w



=



51.05% x 2.621



=



1.338



=



(1 + 51.05%) x 2.621 x 0.996



=



1.687 gr/cc



1+e



1+ 1.338



Ka2 =



tg2 (45 - /2)



=



tg2 (45 - 7/2)



=



0.783 A



Kp =



tg2 (45 + /2)



=



tg2 (45 + 7/2)



=



1.278 A



Q = 5 t/m



H1



Pa1



= 2,5 m



C1



=



 1



=



11 0



=



1.662 gr/cc



d Ka1



=



Pa2



A



Pp1



Pa3



D Pp2



Pa4 B



0.32 kg/cm2



1.06 gr/cc



=



tg (45 - /2)



=



tg2 (45 - 11/2) =



2



C2



=



 2



=



7 0



=



1.687 gr/cc



d Ka2



=



0.980 gr/cc



=



tg2 (45 - 7/2)



Kp



=



tg (45 + /2)



=



tg2 (45 + 7/2) =



a Ttitik A a1



=



Q x Ka1



=



5 x 0.68



= a2



3.40 t/m2



= Ka1 x 1 x H1 - 2 C1 x  Ka1 = 0.68 x 1.662 x 2.5 - 2 x 3.2 x  0.68 =



2.8239



5.276



-2.452 t/m2 (Merupakan tekanan pasif) a diabaikan



= p1



-



= Kp x 2 x H1 - 2 C2 x  Kp = 1.278 x 1.687 x 0 + 2 x 2.6 x  1.278 =



5.878 t/m2



a Ttitik B a3



= 1 x H1 x Ka2 = 1.662 x 2.5 x 0.783 =



a4



3.253 t/m2



= 2 x D x Ka2 - 2 C2 Ka2 = 1.687 x D x 0.783 - 2 x 2.6 x  0.783 =



p2



1.3201 D -



4.601



= Kp x 2 x D = 1.278 x 1.678 x D =



2.155 D t/m2



0.26 kg/cm2



=



2



Pa1



= a1 x H1 = 3.4 x 2.5 =



Pp1



8.49 t



= p1 x D = 5.878 x D



Pa3



= a3 x D = 3.253 x D



a4



= 2 x D x Ka2 - 2 C2 Ka2 = 0 2 x H2 x Ka2 1.687 x X x 0.783 X



=



2 C2 Ka2



=



2 x 2.6 x  0.783



=



2 x 2.6 x  0.783 1.687 x 0.783



X Pa4



=



3.485 m



= (1.321 D - 4.601) x 1/2 (D - 3.483) = 0.6602 D2 - 6.902 D + 16.025 ton



Pp2



= 2.156 D x 1/2 D =



1.077 D2 ton



Keseimbangan  MB = 0



a 8.5 x (1/2 x 2.5 + D) + 3.253 D x 1/2 D + (0.6602 D2 - 6.902 D + 16.025) x 1/3 (D - 3.483) = 5.879 D x 1/2 D + 1.078 D2 x 1/3 D



a 10.625 + 8.5 D + 1.6265 D2 + 0.220 D3 - 2.301 D2 + 5.342 D - 0.766 D2 + 8.013 D - 18.605 = 2.9395 D2 + 0.359 D3



a 0.139 D3 + 4.38 D2 - 21.855 D + 7.98 = 0 Dengan cara coba-coba didapat harga D



=



gr/cc



gr/cc



kg/cm2 gr/cc gr/cc 0.680 kg/cm2 gr/cc gr/cc 0.783 1.278



5



2.5



0.6601



6.901 16.033



10.618



8.494



0.766762 8.016 = 2.938765 12.627 0.139



1.626 0.220



2.300



18.624



0.359 =



3.298



4.379 21.855 8.007



9.054 70.866 87.926 8.007 65.092 16.182 4.0232



0.0000756



5.344



PERENCANAAN SHEET PILE Lokasi STA. 22 + 335.5 Data tanah A



Jenis tanah : lempung berkerikil Kedalaman 0 - 10.2 m :



C =



0.00 kg/cm2



w =



0.996 t/m3



 =



27 0



Gs =



2.53 gr/cc



W = e =



2.625



18.69 % W x Gs



 = (1+W) x Gs x w



=



18.69% x 2.53



=



0.473



=



(1 + 18.69%) x 2.53 x 0.996



=



2.031 gr/cc



=



0.376 A



1+e Ka1 = A



1+ 0.473



tg2 (45 - /2)



tg2 (45 - 27/2)



Kedalaman 10.2 -15 m :



C =



0.02 kg/cm2



w =



0.996 t/m3



 =



26 0



Gs =



Jenis tanah : lempung



2.57 gr/cc



W = e =



=



23.74 % W x Gs



 = (1+W) x Gs x w



2.8675



=



23.26% x 2.57



=



0.610



=



(1 + 23.74%) x 2.57 x 0.996



=



1.967 gr/cc



1+e



1+ 0.61



Ka2 =



tg2 (45 - /2)



=



tg2 (45 - 26/2)



=



0.390 A



Kp =



tg2 (45 + /2)



=



tg2 (45 + 26/2)



=



2.561 A



Q = 5 t/m



Pa1



H1= 10.2 m



Pp1 D Pp2



Pa4 B



a Ttitik A Q x Ka1



=



5 x 0.376



= a2



1.88 t/m2



= Ka1 x  x H1 - 2 C1 xH1x  Ka1 = 0.376 x 2.008 x 10.2 - 2 x 0 x10.2x  0.376 =



7.7781



= p1



-



0.000



7.778 t/m2



= Kp x  x H1 + 2 C2 x H1x Kp = 2.561 x 0.996 x 10.2 + 2 x 0.02 x10.2x  2.561 =



26.671 t/m2



a Ttitik B a3



=  x H1 x Ka2 = 2.031 x 10.2x 0.39 =



a4



8.087 t/m2



= 2 x D x Ka2 - 2 C2 Ka2 = 1.967 x D x 0.39 - 2 x 0.02 x  0.39 =



p2



0.768 D -



0.250



= Kp x 2 x D = 2.561 x 1.975 x D =



-



 1



=



27 0



=



2.031 gr/cc



d Ka1



=



5.038 D t/m2



= =



Pa3



=



=



Pa2



A



a1



C1



kg/cm2



1.82 gr/cc tg (45 - /2) 2



tg2 (45 - 27/2) =



C2



=



 2



=



26 0



=



1.967 gr/cc



d Ka2



=



1.920 gr/cc



=



tg2 (45 - 26/2) =



Kp



=



tg2 (45 + /2)



=



tg2 (45 + 26/2) =



0.02 kg/cm2



Pa1



= a1 x H1 = 1.88 x 4.5 =



Pp1



19.15 t



= p1 x D =



Pa3



= a3 x D =



a4



26.671 x D



8.087 x D



= 2 x D x Ka2 - 2 C2 Ka2 1.975 x D x 0.390 - 2 x 0.02  0.390 2 x H2 x Ka2 1.967 x X x 0.390 X



=



2 C2 Ka2



=



2 x 0.02 x  0.390



=



2 x 0.02 x Ö 0.390 1.967 x 0.390



X Pa4



=



0.325 m



= (0.768 D - 0.25) x 1/2 (D - 0.325) = 0.384 D2 - 0.250 D - 0.125 D + 0.081



Pp2



= p2 x D x 1/2D = 5.038 D x 1/2 D = =



2.519 D2 ton 36.150 ton



Keseimbangan  MB = 0



a Pa1*(2.5+D) + Pa2*(1.5+D)+Pa3*(0.5xD) + Pa4*(D/3-X/3) - Pp1*(0.5xD) - Pp2*(D/3) = 0 a



=



0.001



a Dengan cara coba-coba didapat harga D



=



3.78824



M



Panjang Sheet Pile



=



14.75



M



=



15



M



Dibulatkan menjadi



gr/cc



gr/cc



kg/cm2 gr/cc gr/cc 0.376 kg/cm2 gr/cc gr/cc 0.390 2.561



5



10.2



0.384



D2



2.695



-0.250 -0.125 5.390



D



-0.375 D 0.081



Faktor keamanan = 1,2



PERENCANAAN SHEET PILE Lokasi STA. 2+700 Data tanah A



Kedalaman 0 - 2.5 m :



C =



0.27 kg/cm2



w =



0.996 t/m3



 =



70



Gs =



2.581 gr/cc



W = e =



51.14 % W x Gs



 = (1+W) x Gs x w



=



51.14% x 2.581



=



1.320



=



(1 + 51.14%) x 2.581 x 0.996



=



1.675 gr/cc



=



0.783 A



1+e Ka1 = A



1+ 1.320



tg2 (45 - /2)



tg2 (45 - 7/2)



Kedalaman 2.5 -8.5 m :



C =



0.31 kg/cm2



w =



0.996 t/m3



 =



80



Gs =



2.631 gr/cc



W = e =



=



56.07 % W x Gs



 = (1+W) x Gs x w



=



56.07% x 2.631



=



1.475



=



(1 + 56.07%) x 2.631 x 0.996



=



1.652 gr/cc



1+e



1+ 1.475



Ka2 =



tg2 (45 - /2)



=



tg2 (45 - 8/2)



=



0.756 A



Kp =



tg2 (45 + /2)



=



tg2 (45 + 8/2)



=



1.323 A



Q = 5 t/m



Pa1



H1 = 2,5 m



C1



=



 1



=



7 0



=



1.675 gr/cc



d Ka1



=



Pa2



A



Pp1



Pa3



D Pp2



Pa4 B



=



Q x Ka1



=



5 x 0.783



= a2



tg (45 - /2)



=



tg2 (45 - 7/2)



 2



=



8 0



=



1.652 gr/cc



d Ka2



=



1.020 gr/cc



=



tg2 (45 - 8/2)



Kp



=



tg (45 + /2)



=



tg2 (45 + 8/2) =



= 0.783 x 1.675 x 2.5 - 2 x 0.27 x  0.783 4.778



-1.500 t/m2 (Merupakan tekanan pasif) a diabaikan



= p1



-



= Kp x 2 x H1 + 2 C2 x  Kp = 1.323 x 1.652 x 2.5 + 2 x 0.31 x  1.323 =



12.599 t/m2



a Ttitik B a3



= 1 x H1 x Ka2 = 1.675 x 2.5 x 0.756 =



a4



3.164 t/m2



= 2 x D x Ka2 - 2 C2 Ka2 = 1.652 x D x 0.756 - 2 x 0.31 x  0.756 =



p2



1.249 D -



5.390



= Kp x 2 x D = 1.323 x 1.652 x D =



2.187 D t/m2



=



=



3.91 t/m2



3.2773



2



C2



= Ka1 x 1 x H1 - 2 C1 x  Ka1 =



0.89 gr/cc



=



a Ttitik A a1



0.27 kg/cm2



0.31 kg/cm2



=



2



Pa1



= a1 x H1 = 3.91 x 2.5 =



Pp1



9.78 t



= p1 x D =



Pa3



= a3 x D =



a4



12.599 x D



3.164 x D



= 2 x D x Ka2 - 2 C2 Ka2 1.652 x D x 0.756 - 2 x 0.31  0.756 2 x H2 x Ka2 1.652 x X x 0.756 X



=



2 C2 Ka2



=



2 x 0.31 x  0.756



=



2 x 0.31 x  0.756 1.652 x 0.756



X Pa4



=



4.317 m



= (1.249 D - 5.390) x (1/2 D - 4.317) = 0.624 D2 - 5.390 D - 2.695 D + 23.265



Pp2



= p2 x D x 1/2D = 2.187 D x 1/2 D = =



1.093 D2 ton 10.574 ton



Keseimbangan  MB = 0



a Pa1*(1.25+D) + Pa3*(0.5xD) + Pa4*(D/3-X/3) - Pp1*(0.5xD) - Pp2*(D/3) = 0 a



=



0.057



a Dengan cara coba-coba didapat harga D



=



3.11



M



Panjang Sheet Pile



=



6.23



M



gr/cc



2.52925



gr/cc



2.57712



kg/cm2 gr/cc gr/cc 0.783 kg/cm2 gr/cc gr/cc 0.756 1.323



5



2.5



0.624



D2



-5.390 -2.695 5.390



2.695 D



-8.084 D 23.265



LES GIPSUM Panjang 151.87



Harga satuan 17000



Jumlah Harga 2,581,790



Panjang 61



Harga satuan 60000



Jumlah Harga 3,660,000



Luas 123.09



Harga satuan 115000



Jumlah Harga 14,155,350



29.7475



115000



3,420,963



Topi-topi



68.135



115000



7,835,525



Keliling dibawah atap



LES PLANK Harga bahan



PLAPON



TOTAL



31,653,628



Kamar & teras



Q = 5 t/m



Pa1



H1 = 10.2 m A Pp1



D



Pa2



Pa3



Pp2



Pa4 B



Pa4