15 0 664 KB
Nama
: Ratna Puspitasari
NPM
: 20187279089
Kelas
: 2B
Dosen
: Dr. Mamiek Suendarti, M.Pd
Bab 2 Latihan Hal. 12
2-15. The diameter of a ball bearing was measured by 12 inspectors, each using two different kinds of calipers. The results were. Inspectors
Caliper 1
Caliper 2
1
0.265
0.264
2
0.265
0.265
3
0.266
0.264
4
0.267
0.266
5
0.267
0.267
6
0.265
0.268
7
0.267
0.264
8
0.267
0.265
9
0.265
0.265
10
0.268
0.267
11
0.268
0.268
12
0.265
0.269
(a) Is there a significant difference between the means of the population of measurements from which the two samples were selected? Use 𝛼 = 0.05 (b) Find the P-value for the test in part (a). (c) Construct a 95 percent confidence interval on the difference in mean diameter measurements for the two types of calipers.
Jawab: Input SPSS :
No.
A
Y
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2
.265 .265 .266 .267 .267 .265 .267 .267 .265 .268 .268 .265 .264 .265 .264 .266 .267 .268 .264 .265 .265 .267 .268 .269
Keterangan : A : Cliper Y : Diameter of ball bearing
Output SPSS: Univariate Analysis of Variance Between-Subjects Factors Value Label
N
1
Caliper 1
12
2
Caliper 2
12
Caliper
Tests of Between-Subjects Effects Dependent Variable: The diameter of a ball bearing Source
Type III Sum of
Df
Mean Square
F
Sig.
Squares Corrected Model
3.750E-007a
1
3.750E-007
.164
.689
Intercept
1.700
1
1.700
744164.940
.000
A
3.750E-007
1
3.750E-007
.164
.689
Error
5.025E-005
22
2.284E-006
Total
1.700
24
5.062E-005
23
Corrected Total
a. R Squared = .007 (Adjusted R Squared = -.038)
Analisis Data Hipotesis Statistik H0 : μ A = μ B H0 : μ A ≠ μ B Hipotesis Penelitian H0 : Terdapat pengaruh yang tidak signifikan Caliper terhadap Diameter of Ball bearing H1 : Terdapat pengaruh yang signifikan Caliper terhadap Diameter of Ball bearing
Hasil Statistik Nilai F0 = 0,164 dan Sig = 0,689 > 0,05. Dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang tidak signifikan Caliper terhadap Diameter of Ball bearing.
2-19. In semiconductor manufacturing wet chemical etching is often used to remove silicon from the backs of wafers prior to metalization. The etch rate is an important characteristic of this process. Two different etching solutions are being evaluated. Eight randomly selected wafers have been etched in each solution and the observed etch rates are shown below. Solution 1
Solution 2
9.9
10.2
9.4
10.0
10.0
10.7
10.3
10.5
10.6
10.6
10.3
10.2
9.3
10.4
9.8
10.3
(a) Do the data indicate that the claim that both solutions have the same mean etch rate is valid? Use 𝛼 = 0.05 and assume equal variances. (b) Find a 95 percent confidence interval on the difference in mean etch rates. (c) Use normal probability plots to investigate the adequacy of the assumptions of normality and equal variances. Jawab: Input SPSS :
A
No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
Y 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2
9.9 9.4 10.0 10.3 10.6 10.3 9.3 9.8 10.2 10.0 10.7 10.5 10.6 10.2 10.4 10.3
Keterangan : A : Solution Y : Semiconductor manufacturing
Output SPSS : Between-Subjects Factors Value Label
N
1
Solution 1
8
2
Solution 2
8
Solution
Tests of Between-Subjects Effects Dependent Variable: Semiconductor Source
Type III Sum of Squares
Df
Mean Square
F
Sig.
,681a
1
,681
5,297
,037
1650,391
1
1650,391
12845,292
,000
,681
1
,681
5,297
,037
Error
1,799
14
,128
Total
1652,870
16
2,479
15
Corrected Model Intercept A
Corrected Total
a. R Squared = ,275 (Adjusted R Squared = ,223)
Analisis Data Hipotesis Statistik H0 : μ A = μ B H1 : μA ≠ μB
Hipotesis Penelitian H0
: Terdapat pengaruh yang tidak signifikan Solution terhadap Semiconductor
H1
: Terdapat pengaruh yang signifikan Solution terhadap Semiconductor
Hasil Statistik Nilai F0 = 5,297 dan Sig = 0,037 < 0,05. Dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang signifikan Solution terhadap Semiconductor.
Bab 3 Latihan Hal. 20 3-13 Four chemists are asked to determine the percentage of methyl alcohol in a certain chemical compound. Each chemist makes three determinations, and the results are the following. Chemists
Percentage of Methyl Alcohol
1
84.99
84.04
84.38
2
85.15
85.13
84.88
3
84.72
84.48
85.16
4
84.20
84.10
84.55
(a) Do chemists differ significantly ? use 𝛼 = 0.05 (b) Analyze the residuals from this experiment (c) If chemist 2 is a employee, construct a meaningful set of orthogonal contracts that might have been useful at the start of the experimen Jawab : Input SPSS : No 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12.
A 1 1 1 2 2 2 3 3 3 4 4 4
Y 84.99 84.04 84.38 85.15 85.13 84.88 84.72 84.48 85.16 84.20 84.10 84.55
Output SPSS: Between-Subjects Factors N 1
3
2
3
3
3
4
3
Chemical
Keterangan :
A : Compound Y : Precentage of methyl alcohol
Tests of Between-Subjects Effects Dependent Variable: Precentage of methyl alcohol Source
Type III Sum of
Df
Mean Square
F
Sig.
Squares 1.045a
3
.348
3.246
.081
85984.084
1
85984.084
801529.565
.000
1.045
3
.348
3.246
.081
Error
.858
8
.107
Total
85985.987
12
1.903
11
Corrected Model Intercept A
Corrected Total
a. R Squared = .549 (Adjusted R Squared = .380)
Analisis data Hipotesis Statistik 𝐻0 : 𝜇𝐴 = 𝜇𝐵 = 𝜇𝐶 = 𝜇𝐷 𝐻1 : Bukan 𝐻0 Hipotesis Penelitian H0 : Terdapat pengaruh yang tidak signifikan dari methyl alcohol terhadap chemical compound. H1 : Terdapat pengaruh yang signifikan dari methyl alcohol terhadap chemical compound. Hasil statistik : Nilai F0 = 3.246 dan sig. = 0.081. dikatakan signifikan apabila nilai Sig. < 0,05 Dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang tidak signifikan dari methyl alcohol terhadap chemical compound.
3. 15 Four catalysts that may affect the concentration of one component in a three component liquid mixture are being investigated. The following concentrations are obtained. Catalyst 1 58.2 57.2 58.4 55.8 54.9
2 56.3 54.5 57.0 55.3
3 50.1 54.2 55.4
4 52.5 49.9 50.0 51.7
(a) Do the four catalysts have the same effect on the concentration ? (b) Analyze the residuals from this experiment (c) Construct a 99 percent confidence interval estimate of the mean response for catalyst 1. Jawab : Input SPSS : No 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16.
A
Y
1 1 1 1 1 2 2 2 2 3 3 3 4 4 4 4
58.2 57.2 58.4 55.8 54.9 56.3 54.5 57.0 55.3 50.1 54.2 55.4 52.9 49.9 50.0 51.7
Keterangan :
A : Catalysts Y : Concentration of one component in a three- component liquid
Output SPSS : Between-Subjects Factors N 1
5
2
4
3
3
4
4
Catalyst
Tests of Between-Subjects Effects Dependent Variable: Concentration Source
Type III Sum of
df
Mean Square
F
Sig.
Squares 85.676a
3
28.559
9.916
.001
45584.001
1
45584.001
15827.015
.000
A
85.676
3
28.559
9.916
.001
Error
34.562
12
2.880
Total
47622.440
16
Corrected Model Intercept
Corrected Total
120.237
15
a. R Squared = .713 (Adjusted R Squared = .641)
Analisis data Hipotesis Statistik 𝐻0 : 𝜇𝐴 = 𝜇𝐵 = 𝜇𝐶 = 𝜇𝐷 𝐻1 : Bukan 𝐻0 Hipotesis Penelitian H0 : Terdapat pengaruh yang tidak signifikan dari catalyst terhadap concentration of one component in
a three- component liquid. H1 : Terdapat pengaruh yang signifikan dari catalyst terhadap concentration of one component in a
three- component liquid. Hasil statistik : Nilai F0 = 9, 9169 dan sig. = 0,001 dikatakan signifikan apabila nilai Sig. < 0,05 Dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang signifikan dari catalyst terhadap
concentration of one component in a three- component liquid.
BAB 4 latihan hal 52 4.13 An industrial engineer is conducting an experiment on eye focus time. He is interested in the effect of the distance of the object from the eye on the focus time. Four different distances are of interest. He has five subjects available for the experiment. Because there may be difference among individuals, he decides to conduct the experiment in a randomized block design. The data obtained follow, analyze the data from this experiment (use 𝛼 = 0,05) and draw appropriate conclusions. Distance (Ft)
subject 1
2
3
4
5
4
10
6
6
6
6
6
7
6
6
1
6
8
5
3
3
2
5
10
6
4
4
2
3
Jawab Input SPSS :
No 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. : 12. 13. 14. 15. 16. 17. 18. 19. 20.
A
B
Y
4 4 4 4 4 6 6 6 6 6 8 8 8 8 8 10 10 10 10 10
1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5
10 6 6 6 6 7 6 6 1 6 5 3 3 2 5 6 4 4 2 3
A : Distance B : Subject Y : Eye Focus Time
Output SPSS : Univariate Analysis of Variance Between-Subjects Factors N 4
5
6
5
8
5
10
5
1
4
2
4
3
4
4
4
5
4
Distance
Subject
Tests of Between-Subjects Effects Dependent Variable: Eye Focus Time Source
Type III Sum of
df
Mean Square
F
Sig.
Squares Corrected Model
69.250a
7
9.893
7.759
.001
Intercept
470.450
1
470.450
368.980
.000
A
32.950
3
10.983
8.614
.003
B
36.300
4
9.075
7.118
.004
Error
15.300
12
1.275
Total
555.000
20
84.550
19
Corrected Total
a. R Squared = .819 (Adjusted R Squared = .713)
Analisis Data Hipotesis Statistik Pertama 𝐻0 : 𝜇01 = 𝜇02 𝐻1 : 𝜇01 ≠ 𝜇02 Kriteria Pengujian Hipotesis Tolak 𝐻0 dan terima 𝐻1 : jika nilai sig. < 0.05 Tolak 𝐻0 dan tolak 𝐻1 : jika nilai sig. > 0.05
Kedua 𝐻0 : 𝜇10 = 𝜇20 𝐻1 : 𝜇10 ≠ 𝜇20 Kriteria Pengujian Hipotesis Tolak 𝐻0 dan terima 𝐻1 : jika nilai sig. < 0.05 Tolak 𝐻0 dan tolak 𝐻1 : jika nilai sig. > 0.05 Hipotesis Penelitian Pertama 𝐻0 : terdapat pengaruh yang tidak signifikan distance terhadap eye focus time 𝐻1 : terdapat pengaruh yang signifikan distance terhadap eye focus time Kedua 𝐻0 : terdapat pengaruh yang tidak signifikan Subject terhadap eye focus time 𝐻1 : terdapat pengaruh yang signifikan Subject terhadap eye focus time Hasil Statistik 1. Nilai 𝐹0 = 8.614 dan sig. = 0.003. dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang tidak signifikan distance terhadap eye focus time 2. Nilai 𝐹0 = 7.118 dan sig. = 0.004. dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang signifikan subject terhadap eye focus time. 4.23 Suppose that in Problem 4-15 the engineer suspect that the workplace used by the four operators may represent an additional source of variation . a fourth factor, workplace (𝛼, 𝛽, 𝛾, 𝛿) may be introduced and another experiment conducted, yielding the GraecoLatin square that follower. Analyze the data from this experiment (use 𝛼 = 0.05) and drew conclusions Order of Asembly 1 2 3 4 Jawab: A : Order of Assembly B : Operator C : Latin Square D : Graeco Y : Workplaces used
Operator 1 𝐶𝛽 =11 𝐵𝛼 = 8 𝐴𝛿 = 9 𝐷𝛾 = 9
2 𝐵𝛾 = 10 𝐶𝛽 = 12 𝐷𝛼 = 11 𝐴𝛽 = 8
3 𝐷𝛿 = 14 𝐴𝛾 = 10 𝐵𝛽 = 7 𝐶𝛼 = 18
4 𝐴𝛼 = 8 𝐷𝛽 = 12 𝐶𝛾 = 15 𝐵𝛽 = 6
Input SPSS: No 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16.
A
B
C
D
Y
1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4
1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4
3 2 4 1 2 3 1 4 1 4 2 3 4 1 3 2
2 3 4 1 1 4 3 2 4 1 2 3 3 2 1 4
11 10 14 8 8 12 10 12 9 11 7 15 9 8 18 6
Output SPSS : Between-Subjects Factors Value Label
N
1
4
2
4
3
4
4
4
1
4
2
4
3
4
4
4
Order of Assembly
Operator
Latin Square
1
A
4
2
B
4
3
C
4
4
D
4
1
4
2
4
3
4
4
4
Graeco
Tests of Between-Subjects Effects Dependent Variable: Workplace used Source
Type III Sum of
df
Mean Square
F
Sig.
Squares Corrected Model
122.500a
12
10.208
1.114
.529
Intercept
1764.000
1
1764.000
192.436
.001
A
.500
3
.167
.018
.996
B
19.000
3
6.333
.691
.616
C
95.500
3
31.833
3.473
.167
D
7.500
3
2.500
.273
.843
Error
27.500
3
9.167
Total
1914.000
16
150.000
15
Corrected Total
a. R Squared = .817 (Adjusted R Squared = .083)
Analisis Data Hipotesis Statistik Pertama 𝐻0 : 𝜇01 = 𝜇02 𝐻0 : 𝜇01 ≠ 𝜇02 Kriteria Pengujian Hipotesis Tolak 𝐻0 dan terima 𝐻1 : jika nilai sig. < 0.05 Tolak 𝐻0 dan tolak 𝐻1 : jika nilai sig. > 0.05 Kedua 𝐻0 : 𝜇10 = 𝜇20 𝐻1 : 𝜇10 ≠ 𝜇20 Kriteria Pengujian Hipotesis Tolak 𝐻0 dan terima 𝐻1 : jika nilai sig. < 0.05 Tolak 𝐻0 dan tolak 𝐻1 : jika nilai sig. > 0.05 Ketiga 𝐻0 : 𝜇20 = 𝜇30 𝐻1 : 𝜇20 ≠ 𝜇30 Kriteria Pengujian Hipotesis Tolak 𝐻0 dan terima 𝐻1 : jika nilai sig. < 0.05 Tolak 𝐻0 dan tolak 𝐻1 : jika nilai sig. > 0.05 Keempat
𝐻0 : 𝜇30 = 𝜇40 𝐻1 : 𝜇30 ≠ 𝜇40 Kriteria Pengujian Hipotesis Tolak 𝐻0 dan terima 𝐻1 : jika nilai sig. < 0.05 Tolak 𝐻0 dan tolak 𝐻1 : jika nilai sig. > 0.05 Hipotesis Penelitian Pertama 𝐻0 : terdapat pengaruh yang tidak signifikan Order of Assembly terhadap Workplace used 𝐻1 : terdapat pengaruh yang signifikan Order of Assembly terhadap Workplace used Kedua 𝐻0 : terdapat pengaruh yang tidak signifikan Operator terhadap Workplace used 𝐻1 : terdapat pengaruh yang signifikan Operator terhadap Workplace used Ketiga 𝐻0 : terdapat pengaruh yang tidak signifikan Latin Square terhadap workplace used 𝐻1 : terdapat pengaruh yang signifikan Latin Square terhadap workplaced used Keempat 𝐻0 : terdapat pengaruh yang tidak signifikan Graeco terhadap workplaced used 𝐻1 : terdapat pengaruh yang signifikan Graeco terhadap workplaced used Hasil Statistik 1. Nilai 𝐹0 = 0.018 dan sig. = 0.996. dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang tidak signifikan Order of Assembly terhadap Workplace used 2. Nilai 𝐹0 = 0.691 dan sig. = 0.616 dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang tidak signifikan Operator terhadap Workplace used 3. Nilai 𝐹0 = 3 473 dan sig. = 0.167 dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang tidak signifikan Latin Square terhadap workplace used 4. Nilai 𝐹0 = 0. 273dan sig. = 0.843 dari hasil data di atas dapat disimpulkan bahwa terdapat pengaruh yang yang tidak signifikan Graeco terhadap workplaced used