16 0 212 KB
Tugas Statistika Deskriptif Pertemuan 6 Nama : Siti Nur Nadiah NIM
: 64191365
Kelas : 64.3G.01
Soal Esay 1.
Diketahui: Diberikan data skor hasil ujian statistika dari 12 orang mahasiswa sebagai berikut: 62, 65, 58, 90, 75, 79, 82, 91, 75, 75, 75, 95 Ditanya: Rentang, Rentang antar quartil, Simpangan quartil, Koefisien kurtosis, Koefisien kemiringan, Standar deviasi, Varian, Rerata simpangan Jawab: Urutan Data terkecil-terbesar : 58, 62, 65, 75, 75, 75, 75, 79, 82, 90, 91, 95
Rentang π
= π·π΅ β π·πΎ π
= 95 β 58 = ππ
Rentang Antar Quartil π
π΄π = π3 β π1 π
π΄π = 82 β 65 = ππ
Simpangan Quartil ππ = 1β2 (π3 β π1) ππ = 1β2 (82 β 65) = π, π Koefisien Kurtosis 1 (π3 β π1) πΌ4 = 2 π90 β π10
1 (82 β 85) πΌ4 = 2 93,8 β 59,2 πΌ4 =
8,5 = π, πππ 34,6
Koefisien Kemiringan (πΜ
β ππ) π (76,83 β 75) πΌ3 = = π, πππ 11,53 πΌ3 =
Standar Deviasi βππ₯π 2 β (βππ₯π)2 /π π=β πβ1 72.304 β (922)2 /12 π=β 12 β 1 1.463,6 π=β 11 π = β133,05 = ππ, ππ
ππ ππ πππ ππππ 58 1 3.364 58 62 1 3.844 62 65 1 4.225 65 75 4 5.625 300 79 1 6.241 79 82 1 6.724 82 90 1 8.100 90 91 1 8.281 91 95 1 9.025 95 Total 12 922
πππππ 3.364 3.844 4.225 22.500 6.241 6.724 8.100 8.281 9.025 72.304
Koefisien Varians π π‘πππππ πππ£πππ π π₯ 100% πππ‘π β πππ‘π 11,53 πΎπ = π₯ 100% 76,83 πΎπ =
πΎπ = ππ, ππ%
Rerata Simpangan πΜ
=
58 + 62 + 65 + 75 + 75 + 75 + 75 + 79 + 82 + 90 + 91 + 95 922 = = ππ, ππ 12 12
π
π =
Μ
β|π₯π β π₯| π
|58β76,83|+|62β76,83|+|65β76,83|+|75β76,83|+|75β76,83|+|75β76,83|+|75β76,83|+|79β76,83|+|82β76,83|+|90β76,83|+|91β76,83|+|95β76,83 πΜ
= 12
π
π =
0,04 = π, πππ 12
2.
Diketahui: Data sikap terhadap korupsi dari 20 sample acak disajikan sebagai berikut: 55, 54, 64, 68, 59, 75, 66, 68, 80, 53, 54, 98, 77, 80, 62, 79, 75, 68, 62, 84 Ditanya: Rentang, Rentang antar quartil, Simpangan quartil, Koefisien kurtosis, Koefisien kemiringan, Standar deviasi, Varian, Rerata simpangan Jawab: Urutan Data terkecil-terbesar : 53, 54, 54, 55, 59, 62, 62, 64, 66, 68, 68, 68, 75, 75, 77, 79, 80, 80, 84, 98
Rentang π
= π·π΅ β π·πΎ π
= 98 β 53 = ππ
Rentang Antar Quartil π
π΄π = π3 β π1 π
π΄π = 66 β 54 = ππ
Simpangan Quartil ππ = 1β2 (π3 β π1) ππ = 1β2 (66 β 54) = π Koefisien Kurtosis 1 (π3 β π1) πΌ4 = 2 π90 β π10 1 (66 β 54) πΌ4 = 2 83,6 β 54 πΌ4 =
6 = π, πππ 29,6
Koefisien Kemiringan πΌ3 =
(πΜ
β ππ) π
πΌ3 =
(69,05 β 68) = π, πππ 11,87
Standar Deviasi βππ₯π 2 β (βππ₯π)2 /π π=β πβ1 98.039 β (1.381)2 /20 π=β 20 β 1 2.680,95 π=β 19 π = β141,1 = ππ, ππ
Koefisien Varians
ππ ππ πππ ππππ 53 1 2.809 53 54 2 2.916 108 55 1 3.025 55 59 1 3.481 59 62 2 3.844 124 64 1 4.096 64 66 1 4.356 66 68 3 4.624 204 75 2 5.625 150 77 1 5.929 77 79 1 6.241 79 80 2 6.400 160 84 1 7.056 84 98 1 9.604 98 Total 20 1.381
πππππ 2.809 5.832 3.025 3.481 7.688 4.096 4.356 13.872 11.250 5.929 6.241 12.800 7.056 9.604 98.039
π π‘πππππ πππ£πππ π π₯ 100% πππ‘π β πππ‘π 11,87 πΎπ = π₯ 100% 69,05 πΎπ =
πΎπ = ππ, ππ%
Rerata Simpangan πΜ
=
53 + 54 + 54 + 55 + 59 + 62 + 62 + 64 + 66 + 68 + 68 + 68 + 75 + 75 + 77 + 79 + 80 + 80 + 84 + 98 20
πΜ
=
1.381 = ππ, ππ 20
Μ
β|π₯π β π₯| π 5,68 π
π = = π, πππ 20 π
π =
Soal PG 1. 2. 3. 4. 5.
D. 7 C. 23,02 A. C. 12 B. 3