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PERHITUNGAN TIKUNGAN 1 (LENGKUNG S-C-S)
Kelas VR
=
II A
(tabel)
=
100
(tabel)
α emaks
=
40
p < 0.25 --> Full Circle Lc < 25 --> SS
= =
10% 2%
(tabel) (tabel)
Lc > 25 --> SCS
= = =
477 3 0.035
(tabel)
=
350
e Rc C Γ Rmin
1 Menghitung Jari-Jari Minimum Koefisien gesek f = -0.00065 x v = -0.00065 x = 0.127
+ 100 +
0.192 0.192
Jari - jari minimum Rc
= = =
V2 127 x (emaks + fmaks) 127 x ( 346.87 m
10000 10% +
0.127 )
2 Menentukan panjang lengkung peralihan (Ls) - Berdasarkan lama waktu maksimum Ls
=
T
x
=
3
x
=
VR 3.6 100 3.6
83.33 m
-Berdasarkan antisipasi gaya sentrifugal VR3 Ls = 0.022 x Rc x C = =
0.022
x
19.32 m
1000000 1040.6188
-
2.727 2.727
x x
VR
x
100
x
e C 2% 3
-Berdasarkan tingkat pencapaian perubahan kelandaian em - e n VR Ls = x 3.6 Γ 10% 2% = x 100 3.6 x 0.035 = 63.49 m Ls yang digunakan adalah nilai yang paling besar yaitu
83.33
3 Penentuan Tipe Tikungan Ls2 p = 24 x Rc = =
6944.44 24 x 0.83 m
346.87
4 Perhitungan Tikungan 90 x Ls θs = π x Rc 90 x 3.14 x 6.89
= = θc
Lc
= = = = = =
83.33 346.87
α - 2θs 40 26.23
2x
θc
x 360 26.23 x 360 158.71 m
6.89
2πR 2
x
3.14
x
346.87
Dikarenakan Lc > 25 meter, makan tikungan yang direncanakan adalah Spiral - Circle - Spiral (SCS)
5 Data - Data Tikungan Ls2 Yc = 6Rc = = Xc
=
6944.44 2081.24 3.34 m Ls
-
Ls3
Xc
Ls
=
40R2 578703.70 83.33 4812833.5 83.21 m
= = k
p
Ts
=
Xc
83.21 -
=
42.02
= = =
R sin θs
-
=
346.87 x
3.34 0.88 m
346.87 (
1-
=
(
Rc
+
p
)x
tan
=
(
346.87
+
0.88
)x
tan
) _
Rc
168.59 m
= ( Rc
+
p Δ 2
cos = (
346.87 +
0.88 ) _ 40 2
cos =
Ltotal
0.12
Yc - Rc (1-Cosθs)
= Es
-
= = =
23.20 m
Lc +
2 Ls
158.71 + 166.67 325.37 m
346.87
0.99 )
Δ 2 40 2
+
k
+
42.02
meter.
ah Spiral - Circle - Spiral (SCS)
sin θs
0.118751
cos θs tan Δ/2 = tan 20
0.992924 0.36397
cos 20
0.939693
PERHITUNGAN TIKUNGAN 1 (LENGKUNG S-C-S)
Kelas Kecepatan rencana (VR)
=
II A
(tabel)
=
100
(tabel)
α emaks
=
5o 48' 12.87''
p < 0.25 --> Full Circle Lc < 25 --> SS
= =
10% 0.094
(tabel)
Lc > 25 --> SCS
=
2%
(tabel)
Radius rencana (Rc)
=
477
(tabel)
Radius minimum (Rmin)
= = = = =
350 2 X 3.5 90 3 0.035
Kemiringan superelevasi (e) Kemiringan vertikal (en)
Lebar jalan Lengkung peralihan (Ls) C Γ
1 Menghitung Jari-Jari Minimum Koefisien gesek f = = =
-0.00065 x -0.00065 x 0.127
v
+ 100 +
0.192 0.192
Jari - jari minimum Rc
=
V2 127 x (emaks + fmaks) 10000 127 x ( 10% + 346.87 m
= =
0.127 )
2 Menentukan panjang lengkung peralihan (Ls) - Berdasarkan lama waktu maksimum Ls
=
T
x
=
3
x
=
VR 3.6 100 3.6
83.33 m
-Berdasarkan antisipasi gaya sentrifugal Ls
=
0.022
x
VR3
-
2.727
x
Ls
=
0.022
x
=
0.022
x
=
Rc x C 1000000 1040.6188
-
2.727
x
-
2.727
x
x
VR
19.32 m
-Berdasarkan tingkat pencapaian perubahan kelandaian em - e n Ls = 3.6 Γ 10% = 3.6 x = 63.49 m
2% x 0.035
100
Ls yang digunakan adalah nilai yang paling besar yaitu
3 Penentuan Tipe Tikungan p
Ls2
=
24 x Rc
=
24
=
6944.44 x 0.83 m
346.87
4 Perhitungan Tikungan θs
90 x Ls
=
π x Rc 90 x 3.14 x 6.89
= = θc
Lc
= = = = = =
83.33 346.87
α - 2θs 5o 48' 12.87'' #VALUE! θc
x 360 #VALUE! x 360 #VALUE! m
2x
6.89
2πR 2
x
3.14
x
Dikarenakan Lc > 25 meter, makan tikungan yang direncanakan adalah Spiral - Circle - Spiral (SCS)
5 Data - Data Tikungan Yc
=
Ls2 6Rc
6944.44 2081.24
= = Xc
3.34 m Ls
=
40R2 578703.70 83.33 4812833.5 83.21 m
= = k
p
Ts
=
Xc
83.21 -
=
42.02
346.87 x
3.34 0.88 m
346.87 (
1-
=
(
Rc
+
p
)x
tan
=
(
346.87
+
0.88
)x
tan
) _
Rc
168.59 m
= ( Rc
+
p Δ 2
cos = (
346.87 + cos
=
Ltotal
0.12
Yc - Rc (1-Cosθs)
= Es
R sin θs
-
=
= = =
Ls3
-
= = =
0.88 ) _ 346.87 5o 48' 12.87'' 2
23.20 m
Lc +
2 Ls
#VALUE! + 166.67 #VALUE! m
Δ 2 5o 48' 12.87'' 2
< 0.25 --> Full Circle > 25 --> SCS
VR
x
e
VR
x
100
x
C 2% 3
83.33 meter.
346.87
Circle - Spiral (SCS)
0.99 )
Δ + 2 5o 48' 12.87'' + 2
k 42.02
sin θs
0.118751
cos θs tan Δ/2 = tan 20
0.992924 0.36397
cos 20
0.939693
PERHITUNGAN ALINYEMEN HORISONTAL PERHITUNGAN TIKUNGAN 1 Kelas Jalan Klasifkasi medan
IIA AASHTO 10%
α Mengunakan metode Kecepatan rencana (Vr) Radius minimum (Rmin) Lebar jalan Radius rencana (Rc) Lengkung peralihan (Ls) Kemiringan super elevasi (e) Kemiringan melintang vertikal (en)
5o 48' 12.87'' AASHTO 10% 100 km/jam 350 m 2 X 3.5 m 477 90 0.094 0.094 0.02 2%
