Kumpulan Soal Bilangan Pangkat, Bentuk Akar, Logaritma, SPLV Dan SPTLV [PDF]

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PENILAIAN TENGAH SEMESTER I MATA PELAJARAN MATEMATIKA NAMA Kelas Hari/Tanggal



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Pilihan Ganda 1. Bentuk sederhana dari(𝑝2 )5 × (𝑝2 )3 adalah . . . a. 𝑝16 c. 𝑝14 b. 𝑝15 𝑎 4 𝑎−2 𝑎 −3



2. Bentuk sederhana dari



Skor A



d. 𝑝13



e. 𝑝12



d. 𝑎5



e. 𝑎4



d. 9𝑥 2 𝑦 2



e. 9𝑥 4 𝑦



adalah . . .



a. 𝑎8 b. 𝑎7 c. 𝑎6 2 2 3. Bentuk sederhana dari(3𝑥 𝑦) adalah . . . a. 3𝑥 2 𝑦 2 b. 3𝑥 4 𝑦 2 c. 9𝑥 4 𝑦 2 4. Bentuk sederhana dari 𝑎5 𝑏 2 ÷ 𝑎6 𝑏 adalah . . . 𝑎 a. 𝑎𝑏 b. 𝑎𝑏 2 c. 𝑏



5. Bentuk sederhana dari√72 adalah . . . a. 2 b. 4



d.



𝑏 𝑎



e.



c. 2√6



d. √6



c. 2√2



d. 2√2



𝑏2 𝑎



e. 6√2



3



6. Bentuk sederhana dari√16 adalah . . . a. 2 b. 2 √2 √6



7. Nilai dari 2



3



3



e. √2



adalah . . . b. 2√6



a. √6



c.



1 √6 6



d.



1 √2 6



e. √12



8. Nilai dari 2√54 − √24 + 5√12 = . . . a. 2√6 − 10√3 9. Nilai



4 dari3−√5



d. −2√3 + 10√6



e. −2√6 − 10√3



b. 5 − 2√3



c. 3 − √5



d. √3 + √5



e. √3 − √5



−2



=



b.



6



10. Bentuk logaritma dari 6 6



c. 2√3 + 10√6



=...



a. 3 + √5 a.



b. 2√6 + 10√3



1



𝑙𝑜𝑔 6 = −2



1 36



adalah . . . 1



𝑙𝑜𝑔 36 =− 2



c.



36



1



𝑙𝑜𝑔 6 = 2



d.



6



1



𝑙𝑜𝑔 36 = 2



e.



6



1



𝑙𝑜𝑔 6 = 2



1



11. Nilai logaritma dari √5𝑙𝑜𝑔 25 adalah . . . 12. 13. 14. 15. 16. 17.



a. −2 b. −3 c. −4 d. 4 6 6 6 Nilai logaritma dari log 15 + log 12 + log 5 = . . . a. 5 b. 4 c. 3 d. 2 2 3 5 Hasil dari log 25 × log 4 × log 27 = . . . a. 8 b. 9 c. 10 d. 11 Himpunan penyelesaian dari persamaan 9𝑥 − 7 = 4𝑥 + 18 adalah . . . a. {2} b. {3} c. {4} d. {5} Himpunan penyelesaian dari persamaan 6(𝑦 + 1) = −2(𝑦 − 15) adalah . . . a. {5} b. {4} c. {3} d. {2} Himpunan penyelesaian dari pertidaksamaan 2𝑥 − 4 < 5𝑥 + 8 adalah . . . a. {… ,1,2,3} b. {5,6,7, … } c. {4} d. {5} Himpunan penyelesaian dari pertidaksamaan 5𝑥 + 8 ≤ 2𝑥 + 14 adalah . . . a. {… ,0,1,2} b. {4,5,6, … } c. {2} d. {3}



18. Nilai mutlak dari a. −1



1 |4



−



3 | 2



e. 2 e. 1 e. 12 e. {6} e. {1} e. {6} e. {4}



=...



b.



1 8



c.



1 2



19. Himpunan penyelesaian dari |𝑥 + 2| = 4 adalah . . . a. {2,6} b. {−2,6} c. {−6,2} 20. Himpunan penyelesaian dari|3𝑥 − 5 = 4|jika𝑥 > 1 adalah . . . a. {6} b. {5} c. {4}



1



1 8



e. − 2



d. {−6, −2}



e. {0}



d. {3}



e. {2}



d. −



Skor B NAMA Kelas



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Essay!



1.



𝑎3 𝑏−2 ×𝑎𝑏3



2.



𝑎4 𝑏



Jawab:



log 27 + 9log 27 Jawab: ................................................................................



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3. Tentukan himpunan penyelesaian dari persamaan4(𝑥 + 1) = 12 + 2𝑥 Jawab:



5.



3



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4. Tentukan nilai mutlak dari |2𝑥 + 6 = 4𝑥 − 2|jika𝑥 < 1. Jawab:



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3√2 √6−2√2



Jawab: .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. .............................................................................................................................................................................. ..............................................................................................................................................................................



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